(x+3)*(2x+8)=2x^2+8x+36

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Solution for (x+3)*(2x+8)=2x^2+8x+36 equation: 



(x+3)(2x+8)=2x^2+8x+36

We move all terms to the left:

(x+3)(2x+8)-(2x^2+8x+36)=0

We get rid of parentheses

-2x^2+(x+3)(2x+8)-8x-36=0

We multiply parentheses ..

-2x^2+(+2x^2+8x+6x+24)-8x-36=0

We get rid of parentheses

-2x^2+2x^2+8x+6x-8x+24-36=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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